Question

How many moles of hydrogen, phosphorous and oxygen are present in 0.213 moles of $H_{3}PO_{4}$ (Phosphoric acid)?

Answer 1

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Answer 2

$H_{3}PO_{4}$ represents 1 mole of phosphorous acid which contains 3 hydrogen , 1 phosphorous and 4 oxygen atoms.

We know that, $H_{2}$ represents 1 hydrogen gas molecule means 1 mole of hydrogen gas.

Therefore, in 1 mole hydrogen = 2H and 3H is equivalent to 1.5 mole hydrogen which is present in 1 mole of Phosphoric acid ($H_{3}PO_{4}$).

Now, 0.213 mole phosphoric acid contains (0⋅213 × 1⋅5) = 0⋅3195 mole of hydrogen.

P refers to 1 mole of phosphorous. So, 0.213 mole phosphoric acid contains (0⋅213 × 1) = 0⋅213 mole of phosphorous.

Similarly $O_{2}$ represents 1 mole of oxygen gas . Here 1 mole $H_{3}PO_{4}$ contains 2 mole oxygen.

Therefore 0.213 mole phosphoric acid contains (0⋅213 × 2) = 0⋅426 mole of oxygen.