Question

How many moles and how many gram of Nacl are present in 250ml of 0.50M in a solution

Answer 1

Bonjour!

No. of moles = ?
Gram of NaCl = ?
Molecular weight of NaCl = 58.5 g
Volume of solution = 250 ml
Molarity = 0.50 M or M/2


$molarity = \frac{mole \: of \: solute(nacl)}{volume \: of \: solution \: in \: liters}$

So,
$= > \frac{1}{2} = \frac{mole \: of \: nacl}{ \frac{250}{1000} } \\ \\ = > \frac{1}{2} = \frac{mole \: of \: nacl}{ \frac{1}{4} } \\ \\ = > mole \: of \: nacl = \frac{1}{2 \times 4} = \frac{1}{8} mol$

So, Mole of NaCl = 1/8 mol

As we know;
$no. \: of \: mole \: = \frac{given \: weight}{molecular \: weight}$

So,
$= > \frac{1}{8} = \frac{given \: weight}{58.5} \\ \\ = > given \: weight = \frac{58.5}{8} = 7.3125gm$
Therefore there are 1/8 mole and 7.3125 gm of NaCl present in 250 ml of 0.50M solution.

Hope this helps...:)

Answer 2

Answer:

No. of moles =    ?

Gram of NaCl =   ?

Molecular weight of NaCl = 58.5 g

Volume of solution = 250 ml

Molarity = 0.50 M or M/2

Mole of NaCl = 1/8 mol

Therefore there are 1/8 mole and 7.3125 gm of NaCl present in 250 ml of 0.50M solution.

Explanation: