How many moles are present in
(a) 0.25g of CaCO3
b) 5.72g of Naco2
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mole= given mass of substance/ molecular mass
mole= 0.25/ 100 ( molecular mass of CaCO3 is 100)
mole= 0.0025 mol
mole= 5.72/67 (molecular mass of NaCO2 is 67)
mole= 0.085 mole
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