Chemistry, asked by prakashgyanendra634, 6 hours ago

How many moles of calcium carbonate (CaCO3) are present in 10 g of the substance

Answers

Answered by Anonymous

0

Answer:

0.1

Explanation:

Molar mass = 40 + 12 + 48

= 100

Moles = mass /molar mass

= 10/ 100

= 0.1

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