How many moles of calcium carbonate (CaCO3) is in a 2.22g sample?
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Molecular weight of CaCO3 → 40+12+48 = 100g
So,
100g → 1 mole
1 g → 1/100 mole
2.22g → 1/100 ×2.22
Answer come out to be 0.0222 moles
So,
100g → 1 mole
1 g → 1/100 mole
2.22g → 1/100 ×2.22
Answer come out to be 0.0222 moles
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