Question

how many moles of carbon dioxide liberated when 5 moles of acetylene undergoes combustion​

Answer 1

Given that :-

• 5 mole of Acetylene undergoes combination

Combustion :-

Combustion is a chemical process in which hydrocarbon react with oxygen and give the molecule of carbon dioxide and water .

√ According to this question

5C2H2 + O2 ------------->. CO2. + H2O

Now balancing the equation

$5 \: C_{2} H_{2} \: + \frac{25}{2}O_{2} \: \: \: &#10141 \: 10C O_{2} \: \: + \: \:5 H_{2}O$

• 10 mole of carbon dioxide is formed ..

Answer 2

Answer:

10 moles of carbon dioxide is liberated when 5 moles of acetylene undergoes combustion​.

Explanation:

The balanced equation for the combustion of acetylene is:

$2C_{2} H_{2} + 5O_{2}$ → $4CO_{2} + 2H_{2} O$

Given number of moles of acetylene = 5 moles

According to the balanced equation,

2 moles of acetylene gives 4 moles of carbon dioxide

⇒5 moles of acetylene gives $\frac{4*5}{2}$ = 10 moles of carbon dioxide.

Therefore, 10 moles of carbon dioxide is liberated when 5 moles of acetylene undergoes combustion​.