how many moles of ethane are required to produce 44g of CO2 after the combustion of ethane?
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Answered by
27
Reaction for the combustion of the Ethane is ⇒
___________________________
2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
___________________________
From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
Answered by
29
Answer:
➡Reaction for the combustion of the Ethane is ⇒
______________________
2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
______________________
➡From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
Explanation:
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