How many moles of ethane is required to produce 44 g of co2 g after combustion
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Answer:
Reaction for the combustion of the Ethane is -
2C²H6 + 7O² ----------->4CO² + 6H²O
From this reaction,
Since, 4 mole of the carbon dioxide is prepared by the 2 mole of the Ethane.
Therefore, 1 mole of the carbon dioxide is prepared by the 0.5 mole of the Ethane
since, 1 mole of the carbon dioxide = 44g
Therefore, moles of the Ethane required for the combustion is 0.5 moles.
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