How many moles of ethane is required to produce 44 g of CO2 (g) after combustion.
Answers
Answered by
143
Reaction for the combustion of the Ethane is ⇒
___________________________
2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
___________________________
From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
Hope it helps.
___________________________
2C₂H₆ + 7O₂ ----------→ 4CO₂ + 6H₂O
___________________________
From this reaction,
∵ 4 mole of the Carbon dioxide is prepared by the 2 mole of the Ethane.
∴ 1 mole of the Carbon dioxide is prepared by the 0.5 mole of the Ethane.
∵ 1 mole of the Carbon dioxide = 44 g.
∴ Moles of the Ethane required for the combustion is 0.5 moles.
Hope it helps.
Answered by
12
Answer:
Yr..its difficult but acc to me ans is 0.5 mol
Explanation:
Similar questions