Question

how many moles of ethanol are present in a 100.0 g sample of ethanol?

Answer 1

molar mass CH3CH2OH = 46.07 g/mol 
moles = mass / molar mass = 100.0 g/ 46.07 g/mol=2.17

Answer 2

2.173 moles of ethanol are present in a 100.0 g sample of ethanol.

Explanation:

The 'amount of substance' that contains as 'many particles' as there are atoms in exactly '12 g of Carbon'- 12 isotope is called one mole.

Atomic masses of carbon (C), hydrogen (H) and oxygen (O) is 12 u, 1 u and 16 u respectively. So, molecular mass of ethanol $(CH_3 CH_2 OH)$ is

$=24+6+16$

= 46 u.

Moles present in ethanol in 100.0 g sample of ethanol will be

$=\frac{100}{46}$

$=2.173$ moles.

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