Question

How many moles of F2 are required to produced 8.3 moleso
HF?​

Answer 1

Answer:

First, write down the balanced equation.

2NH3+5F2→N2F4+6HF

Find out the limiting reactant in this equation. According to the balanced equation:

2 moles of NH3 should react with 5 moles of F2

So, 1 mole of NH3 should react with 5/2 moles of F2

Therefore, 2.22 moles of NH3 should react with 5.55 moles of F2

But there are only 5.33 moles of F2 . So, F2 is the limiting reagent. We have to now base our calculations with this.

Now, according to the balanced equation:

5 moles of F2 gives 6 moles of HF

1 mole of F2 gives 6/5 moles of HF

5.33 moles of F2 gives 6.40 moles of HF

Therefore,

6.40 moles of HF were produced.