Question

How many moles of glucose (C­6H12O6) are produced when of 51 moles of carbon dioxide (CO2) are consumed?

0.12 moles of glucose

8.5 moles of glucose

51 moles of glucose

1.75 moles of glucose

Answer 1

0.12 moles of glucose

Answer 2

8.5 moles of glucose produced when of 51 moles of carbon dioxide  are consumed.

Explanation:

The balanced chaemical reaction for photosynthesis is:

$6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2$

According to stoichiometry

6 moles of carbon dioxide $CO_2$ produces 1 mole of glucose $C_6H_{12}O_6$

Thus 51 moles of carbon dioxide $CO_2$ produces = $\frac{1}{6}\times 51=8.5$ moles of glucose $C_6H_{12}O_6$

Thus 8.5 moles of glucose produced when of 51 moles of carbon dioxide  are consumed.

Learn more about stoichiometry

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