Question

how many moles of HCL will be present in hundred ml of a solution of specific gravity 1.08 containing 20% of HCL by mass​

Answer 1

volume of solution = 100 ml

specific gravity = 1.08

density = 1.08 g/mL

mass of solution = 100 × 1.08 = 108 g

Mass of HCl present = 108 × 20 / 100 = 21.6 g

No. of moles of HCl = 21.6 / 36.46 = 0.592

Answer 2

Answer:

0.592

Explanation:

volume of solution = 100 ml

specific gravity = 1.08

density = 1.08 g/mL

mass of solution = 100 × 1.08 = 108 g

Mass of HCl present = 108 × 20 / 100 = 21.6 g

No. of moles of HCl = 21.6 / 36.46 = 0.592