how many moles of HCL will be present in hundred ml of a solution of specific gravity 1.08 containing 20% of HCL by mass
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volume of solution = 100 ml
specific gravity = 1.08
density = 1.08 g/mL
mass of solution = 100 × 1.08 = 108 g
Mass of HCl present = 108 × 20 / 100 = 21.6 g
No. of moles of HCl = 21.6 / 36.46 = 0.592
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Answer:
0.592
Explanation:
volume of solution = 100 ml
specific gravity = 1.08
density = 1.08 g/mL
mass of solution = 100 × 1.08 = 108 g
Mass of HCl present = 108 × 20 / 100 = 21.6 g
No. of moles of HCl = 21.6 / 36.46 = 0.592
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