How many moles of He are present in 104g of He
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Given mass, m = 104g
He, M= 4u
No.of moles, n = m/M = 104/4 = 26
No. of molecules = n × avagadro no. = 26 × 6.022×10^23 = 156.572 × 10 ^23 or 1.567 ×10^25.
....hope you got it.
He, M= 4u
No.of moles, n = m/M = 104/4 = 26
No. of molecules = n × avagadro no. = 26 × 6.022×10^23 = 156.572 × 10 ^23 or 1.567 ×10^25.
....hope you got it.
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