how many moles of helium are present in 104g of He
Answers
Answered by
0
Answer:
26
Explanation:
U just simply divide 104 by 4 to get the answer that is 26.
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Answered by
1
Answer:
4g of He= 1 mole
1g of He = 1/4 mole
104g of He = 1/4x104
= 104/4=26 moles
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