Question

How many moles of helium gas occupy 22.4 L at 0 degree Celsius at 1 ATM pressure

Answer 1

n = ?

V = 22.4 l

P = 1 atm

T = 0℃ = 273k


Apply. PV = n RT

1 × 22.4 = n × 0.0821 × 273

n = 22.4 / 22.4

n = 1

Hence it contains 1 mole.


Thanks

Answer 2

Answer:

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