how many moles of iodine can be obtained from 0.2 moles of potassium iodate ( v )?
KLO3(aq)+5 Kl(aq) +6HCl(aq) gives 3l2(aq)+6KCl(aq)+3H2O(l)
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I −
is oxidized
.
IO
3
−
is reduced to I
2
.
Oxidation number of I increases from −1 (in KI) to zero (in I and 2).
Hence, option A is correct.
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