How many moles of ions are there in 10 g of magnesium phosphate, Mg3(PO4)2?
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Answer:
no of moles = 5[10/262]
= 0.19
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The no. of moles of ions in 10 g of magnesium phosphate, Mg₃(PO₄)₂ is 0.19 moles.
- The dissociation of Mg₃(PO₄)₂ into its ions is given as
Mg₃(PO₄)₂ ⇄ 3Mg²⁺ + 2 PO₄³⁻
i.e., 1 mole of Mg₃(PO₄)₂ gives 5 moles of ions
⇒ 263 gm gives 5 moles of ions. (Molar mass of Mg₃(PO₄)₂ = 263 gm)
- 1 gm of Mg₃(PO₄)₂ will give ions = 5/263
- So 10 gm of Mg₃(PO₄)₂ will give ions = 5× 10/263 =50/263 = 0.19
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