Question

how many moles of iron are present in a pure sample weighing 558.45g ? ( molar mass of iron is 55.845g)​

Answer 1

Given,

A pure sample of iron has a mass = 558.45 g

To find,

The number of moles of iron present in the given pure sample.

Solution,

We can simply solve this numerical problem by using the following process:

As per stoichiometry;

1 mole of any element contains Avogadro's number of atoms, that is, 6.022 x 10^23 atoms, and has a mass equal to its molar mass.

The molar mass of any element is equal to the atomic mass of the same element.{Statement-1}

Now, according to the question and statement-1;

The molar mass of iron = 55.845 g

=> 55.845 g of iron is equivalent to 1 mole

=> 1 g of iron is equivalent to (1/55.845) moles

=> 558.45 g of iron is equivalent to (1/55.845)×558.45 moles

=> 558.45 g of iron is equivalent to 10 moles of iron

=> the given pure sample of iron contains 10 moles of iron

Hence, the given pure sample of iron contains 10 moles of iron.

Answer 2

Answer:

The molar mass of iron is 55.845 g/mol. Therefore, the number of moles of iron in the pure sample weighing 558.45 grams is: = 10 moles

Explanation:

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