Question

How many moles of k2 cr2 o7 are reduced by 1 mole of formic acid?

Answer 1

Answer:

Explanation:

Cr2 O7 + 8H + 3HCOOH → 2Cr3 + 3CO2 + 7H2 O Q 3 moles of formic acid reduces = 1 mole K2 Cr2 O7 ∴ 1 mole of formic acid reduce = 3 1 mole K2 Cr2 O7 Ans is 1/3 mole

Answer 2

Given:

No of moles of Formic Acid = 1

To Find:

No of moles of K₂Cr₂O₇ reduced by 1 mole formic acid.

Calculation:

- The reduction of K₂Cr₂O₇ by formic acid can be depicted as:

Cr₂O₇²⁻ + 3 HCOOH + 8 H⁺ → 2 Cr³⁺ + 3 CO₂+  7 H₂O

- From the above equation, we get:

No of moles of K₂Cr₂O₇ reduced by 3 moles of Formic acid = 1

⇒ No of moles of K₂Cr₂O₇ reduced by 1 moles of Formic acid = 1 / 3 = 0.33 moles

- So, 0.33 moles of K₂Cr₂O₇ are reduced by 1 moles of Formic acid.