Question

How many moles of lead(II)chloride will be formed when 2 moles of PbO reacts with 2 moles of HCl
1 point
1 mol
2 mol
3 mol
4 mol

Answer 1

Answer:

Answer is given below

Explanation:

PbO+2HCl→PbCl  

2

​  

+H  

2

​  

O

Atomic mass of PbO = 207 + 16 = 223

Atomic mass of HCl = 36.5

Moles of PbO =  

223

6.5

​  

 = 0.029 moles

Moles of HCl =  

36.5

3.2

​  

 = 0.088 moles

From the above chemical equation, we see that PbO is the limiting reagent.

∴ 1 mole of PbO gives 1 mole of PbCl  

2

0.029 moles of PbO forms 0.029 moles of PbCl  

2

Answer 2

Answer:

The number of moles of lead (II) chloride ( $PbCl_{2}$ ) formed when $2moles$ of $PbO$ reacts with $2moles$ of $HCl$ = $2mol$.

Therefore, option b) $2mol$ is correct.

Explanation:

Given data,

The number of moles of $PbO$ = $2moles$

The number of moles of $HCl$ = $2moles$

The number of moles of lead (II) chloride ( $PbCl_{2}$ ) formed when $2moles$ of $PbO$ reacts with $2moles$ of $HCl$ =?

As we know,

• When one mole of $PbO$ reacts with $2moles$ of  $HCl$ gives one mole of $PbCl_{2}$ as shown below;
• $PbO + 2HCl \rightarrow PbCl_{2} + H_{2}O$

Here, we can see;

• $PbO$ is the limiting reagent ( completely used up in the reaction ).

So,

• The formation of the $PbCl_{2}$ will be dependent on the amount of $PbO$.

Therefore,

• $1 mole$ of $PbO$ yields = $1mole$ of $PbCl_{2}$

Thus,

• $2 moles$ of $PbO$ yields = $2moles$ of $PbCl_{2}$

Hence, the number of moles of lead (II) chloride ( $PbCl_{2}$ ) formed when $2moles$ of $PbO$ reacts with $2moles$ of $HCl$ = $2mol$.

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