how many moles of magnesium phosphate Mg3(PO4)2 WILK Contain 0.25 mole of oxygen atoms
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Solution :
We know,
1 mole of Mg₃(PO)₄ = 8 moles of oxygen atoms
So,
1 mole of oxygen atoms = (1/8) moles of Mg₃(PO)₄
0.25 moles of oxygen atoms = [(1/8)×0.25] moles of Mg₃(PO)₄
= 0.3125 moles of Mg₃(PO)₄
Hence, 0.3125 moles of Mg₃(PO)₄ contain 0.25 moles of oxygen atoms.
We know,
1 mole of Mg₃(PO)₄ = 8 moles of oxygen atoms
So,
1 mole of oxygen atoms = (1/8) moles of Mg₃(PO)₄
0.25 moles of oxygen atoms = [(1/8)×0.25] moles of Mg₃(PO)₄
= 0.3125 moles of Mg₃(PO)₄
Hence, 0.3125 moles of Mg₃(PO)₄ contain 0.25 moles of oxygen atoms.
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