how many moles of Na are present in 120 g sodium sulphate
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Answer:
3 mole
Explanation:
Molar mass of sodium hydroxide =40
No. of moles =Mass/Molar mass
No. of moles (n) = 120/40
=3 moles
There are N formula units per gram formula weight. 120 grams of NaOH means 3 Moles of NaOH because 40 grams (Molecular Weight in grams) is one mole of NaOH. Each mole of any substance contain Avogadro's number of molecules ie., 6.022 x (10 to the power 23
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