Question

how many moles of NA2CO3 are present in 212g of it? ​

Answer 1

Answer:

2 moles of Na2CO3 are present in 212g of it.

Explanation:

As we know,

Moles= given weight/molecular weight

so molecular weight of Na2CO3 = 106g/mol

therefore moles= 212/106 = 2 moles

Answer 2

MOLES -

• The measurement unit of small entities such as atoms, molecules, and other particles.
• Moles can be calculated as the number of particles present in 12g of a carbon atom.
• Moles can be calculated by the division of weight and molecular weight.
• In the given sodium carbonate compound,

Weight = 212g

Molecular weight = 106g

Moles = $\frac{212}{106}$

n = 2 moles

Two moles of sodium carbonate are present in 212g of it.