Question

How many moles of Na2S2O3 can be produced from 32 g of sulphur?
a 1.0
b 0.50
c 79
d 158​

Answer 1

Answer:

Mass of sulphur = 32 gm We know 1 mole of sulphur = molar mass of sulphur Molar mass of sulphur = 32 gm so 32 gm of sulphur is 1 mole of sulphur

Explanation:

Answer 2

$\bigstar$ Answer $\bigstar$

$\checkmark$ To Find:

How many moles of $\sf Na_{2}S_{2}O_{3}$ can be produced from 32 g of Sulphur

• (a) 1.0
• (b) 0.50
• (c) 79
• (d) 158​

$\checkmark$ Solution:

We know that,

1 mole of Sulphur contains 32 g of Sulphur

Given that,

$\star$ 32 g of Sulphur

Hence,

Number of Moles of Sulphur

$\implies \sf No. \ of \ Moles = \dfrac{32}{32}=1 \ mole$

Also,

$\star$ Given Compound: $\sf Na_{2}S_{2}O_{3}$

Compound Name: Sodium Thiosulphate

We know that,

1 mole of $\sf Na_{2}S_{2}O_{3}$ will be obtained from two moles of Sulphur

Or,

2 moles of Sulphur will be required to obtain 1 mole of $\sf Na_{2}S_{2}O_{3}$

Mathematically,

$\sf 2 \ mole \ Sulphur \longrightarrow 1 \ mole \ of \ Na_{2}S_{2}O_{3}$

$\sf 1\ mole \ Sulphur \longrightarrow "\;x\;" \ mole \ of \ Na_{2}S_{2}O_{3}$

Given that,

$\star$ 32 g of Sulphur = 1 mole of Sulphur

Hence,

According to the the Question,

We are asked to find the number of moles $\sf Na_{2}S_{2}O_{3}$ can be produced from 32 g of sulphur

Therefore,

We should find "x"

From the representation,

$\sf 2 \ mole \ Sulphur \longrightarrow 1 \ mole \ of \ Na_{2}S_{2}O_{3}$

$\sf 1\ mole \ Sulphur \longrightarrow "\;x\;" \ mole \ of \ Na_{2}S_{2}O_{3}$

By Cross multiplication,

We get,

$\blue{\sf \implies x=\dfrac{1 \times 1}{2} \ moles \ of \ Na_{2}S_{2}O_{3}}$

$\green{\sf \implies x=\dfrac{1}{2} \ moles \ of \ Na_{2}S_{2}O_{3}}$

$\red{\sf \implies x=0.5 \ moles \ of \ Na_{2}S_{2}O_{3}}$

Therefore,

0.5 moles of $\sf Na_{2}S_{2}O_{3}$ can be produced from 32 g of Sulphur

Hence,

$\checkmark$ Option (b) is correct