Question

How many moles of NaOH are contained in 27ml of 0.15M NaOH solution?

Answer 1

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Answer 2

Answer: $4.05\times 10^{-3}$ moles

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{moles}{\text {Volume in L}}$

Given Molarity of $NaOH$ = 0.15 M

Volume of $NaOH$ = 27 ml= 0.027 L  (1L= 1000 ml)

Thus $Moles=Molarity\times {\text {Volume in L}}=0.15\times 0.027= 4.05\times 10^{-3}$