Question

How many moles of O2 are required to react completely with 1.396 g of Fe?

Answer 1

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Answer 2

for formation of FeO,

2Fe + O2→2FeO

mass of Fe = 56gm

by stiochiometry, 2 moles of Fe will react .

1.396g is nearly equal to 25/1000 i.e 0.025 moles of Fe

2 mol Fe → 1 mol O2

1 mol Fe→1/2 mol O2

for 0.025 mol of Fe →1/2 x 0.025

=0.0125 moles

for Fe2O3

4 Fe +3O2→2 Fe2O3

here 4 mole of Fe will react with 3 moles of O2

so,

4 mol Fe →3 mol O2

1 mol Fe → 3/4 mol O2

for 0.025 mol Fe → 0.025x3/4

=0.01875 moles of O2

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