Question

How many moles of O2 in this equation
2C6H14 + 19O2 = 12CO2 + 14H2O

Answer 1

Answer:

You will need 41.3 g of oxygen.

The balanced equation is

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

Step 1. Calculate the moles of C₆H₁₄

11.7

g C₆H₁₄

×

1 mol C₆H₁₄

86.17

g C₆H₁₄

=

0.1358 mol C₆H₁₄

Step 2. Calculate the moles of O₂

0.1358

mol C₆H₁₄

×

19 mol O₂

2

mol C₆H₁₄

=

1.290 mol O₂

Step 4. Calculate the mass of O₂

1.290

mol O₂

×

32.00 g O₂

1

mol O₂

=

41.3 g O₂

Explanation:

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