How many moles of oxygen (O2) are present in 33.6 L of the gas at 1 atm and 0°C?
1.5
2
22.4
32
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The answer to this question is 1.5 moles. You can consider the equation of gas PV is nRT. The temperature is converted into Kelvin.
Then the temperature is 273 kelvin. Then you can proceed the step which is 1×33.6 = n× 0.0821×273. Finally, you can get the number of moles n which is calculated as 1.5.
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