Question

How many moles of Pb(NO₃)2 are required
to produce 48 g of O2?​

Answer 1

Answer:

Amount of oxygen liberated should be equated to its equivalent number of moles of lead nitrate. Hence we can convert the amount of oxygen to number of moles.

32g of oxygen =1mole

Hence 48 g =( 1x48)/32= 1.5 moles

2Pb(NO3)2 -------2 PbO + 4NO2+O2

According to this equation 2 moles of lead nitrate gives 1 mole of oxygen

1mole of oxygen = 2 moles of lead nitrate

Hence 1.5 moles of oxygen = 2×1.5 = 3 moles of lead nitrate.

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