Question

How many moles of sodium atoms are present in 2.3g Na ?​

Answer 1

Answer:

0.1 mole

Explanation:

Molecular mass of Sodium is 23 u. So, 23 g of Sodium (Na) is equal to 1 mole of Na.

Number of moles of Na present in 2.3 g of Na = Given mass of Na / Molar mass of Na = 2.3 / 23 = 0.1 mole

Answer 2

Answer:

0.1 moles of Na atoms are present in the 2.3g Na

Explanation:

Given that,

mass of Na = 2.3 g

molar mass of Na = 23  g/mol.

number of moles of Na = given mass of Na / molar mass of Na

⇒                                    = 2.3 g / 23 gmol⁻¹  = 0.1 mol.

Hence, 0.1 moles of Na are present in 2.3 g Na