How many moles of sodium bicarbonate are needed to neutralise 0.8 ml of sulphuric acid
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Answer:
The answer is 0.03 moles
Step-by-step explanation:
According to the information you have given, I would assume that 0.8 ml is 100% pure and hence we will use the density of pure 100% sulphuric acid which is 1.8391 g/ml
Therefore mass is 0.8 x 1.8391 = 1.471 g
moles of H2SO4 = 1.471/98 = 0.015 moles.
equation for reaction 2NaHCO3 + H2SO4 → Na2SO4 + 2H2O + 2CO2
Hence taking mole ratio 2:1
Therefore moles of 2NaHCO3 is 2 x 0.015
= 0.03 moles.
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