Question

how many multiples of 3 lie between 14 and 310.

plz answer this question.​

Answer 1

Answer:

answer is 106

103×3=309

3×5=15

309-4=106

Answer 2

The total number of terms multiple of 3 is 99.

Step-by-step explanation:

The multiples of 3 lies between 14 and 310 are:

15, 18, 21, ..........., 309

The given series are in AP.

Here, first term (a) = 15, common difference (d) = 18 - 15 = 3 and $a_{n} =309$

Let n be the number of term.

To find, the number of terms(n) = ?

We know that,

The nth term of an AP.,

$a_{n} =a+(n-1)d$

∴ 15 + (n - 1)3 = 309

⇒ (n - 1)3 = 309 - 15 = 294

⇒ n - 1 = $\dfrac{294}{3} =98$

⇒ n = 98 + 1 = 99

Thus, the total number of terms multiple of 3 is 99.