How many multiples of 4 lie b/w 10 and 250.also find their sum.
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12, 16,... 248
a=12 d=4
Tn=a+(n-1)d
248=12+(n-1)4
248=12+4n-4
248 =8+4n
248-8=4n
240/4=n
n=60
Sum=n/2(2a+(n-1)d
=60/2(2*12+(60-1)4
=30(24+236)
=30(260)
=7800
a=12 d=4
Tn=a+(n-1)d
248=12+(n-1)4
248=12+4n-4
248 =8+4n
248-8=4n
240/4=n
n=60
Sum=n/2(2a+(n-1)d
=60/2(2*12+(60-1)4
=30(24+236)
=30(260)
=7800
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