How❓many mulyiples of ➡4 lie between❗ 10 and 240?Also find their sum.
shivamraikuni:
use formula of summation in AP
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first Multiple 4 last multiple 236 comman difference 4
by using an=a1+(n-1)d
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Answer:A.P. = 12, 16, 20, 24, 28, .....248
a = 12, d = 14, an = 248
an = a + (n-1) d
248 = 12 + (n-1)4
n - 1 = 236/4
n = 59 + 1 = 60
Sn = (n/2) + (a + an) = (60/2) + (12+248) = 7800
its between 10 to 240 so you can't take 240
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