Question

How❓many mulyiples of ➡4 lie between❗ 10 and 240?Also find their sum.​

Answer 1

first Multiple 4 last multiple 236 comman difference 4

by using an=a1+(n-1)d

Answer 2

Answer:A.P. = 12, 16, 20, 24, 28, .....248

a = 12, d = 14, an = 248

an = a + (n-1) d

248 = 12 + (n-1)4

n - 1 = 236/4

n = 59 + 1 = 60

Sn = (n/2) + (a + an) = (60/2) + (12+248) = 7800