how many Na electrons is present in 5.1g NH3
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Answered by
3
Answer:
14.44 * 10^23 electrons are present in 5.1 g NH3
Explanation:
17 is the molar mass of NH3
5.1 /17 gives the number of moles of NH3 in 5.1 grams of it.
Multiplying by 8 because in 1 mol NH3 there are 8 electrons. (Refer Lewis dot structure of NH3).
Hence in 5.1 g 6.02 * 10^23 times electrons would be present.
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Answered by
1
Answer:
14.44 × 10²³
this is correct answer
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