Question

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Answer 1

Step-by-step explanation:

Given : two Zero is - 2 and 3

Eqⁿ is x²+(a+1)x+b

Here, a = 1, b = a+1 ; c = b

We know that,

Sum of zero => - 2+3 = - b/a

=> 1 = ( - a-1)/1

=> 1 +1 = - a

=> 2 = - a

=> a = - 2

Similarly,

Products of zero => - 2×3 = c/a

=> - 6 = b/1 =b

Hence, a= - 2 and b = - 6

Answer 2

Answer:

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