Question

how many natural number are three between 200 and 500, which are divisible by 7​

Answer 1

Answer:

43 numbers are divisible by 7 b/w 200-500

Step-by-step explanation:

First no. divisible by 7 b/w 200 and 500 = 203

Last no. divisible by 7 b/w 200 and 500 = 497

Difference between two consecutive terms (d) = 7

an = a + (n - 1)d

⇒ 497 = 203 + (n-1)7

⇒ 497 - 203 = 7n - 7

⇒ 294 + 7 = 7n

⇒ 301/7 =n

43 = n

43 numbers are divisible by 7 b/w 200-500.

Answer 2

Answer:

$\red\bigstar$There are 43 numbers between 200 and 500 which are divisible 7.

   SOLUTION  

First number between 200 and 500  which is divisible by 7 = 203

Final number between 200 and 500 which is divisible  by 7 = 497

$\implies$

First Term (an) = 203

Last Term (n) = 497

Common Difference (d) = 7

$\bigstar$ We know the formula of an :-

an = a + (n - 1)d

$\implies$

497 = 203 + ( n - 1 ) 7

$\implies$

497 = 203 + 7n - 7

$\implies$

497 - 203 = 7n - 7

$\implies$

294 + 7 = 7n

$\implies$

301 = 7n

$\implies$

$\sf n = \dfrac{301}{7}$

$\implies$

n = 43

Therefore there are 43 numbers between 200 and 500 ,  which are divisible by 7​.