Question

how many natural number between 101and 999 divisible by 2 and 5 find it using concept of AP


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Answer 1

Answer:

500 is write

Answer 2

Step-by-step explanation:

The list of numbers between 101 and 999 that are divisible by 2 and 5 are:

110,120,130,...990

The numbers are in A.P, with first term, a=110, common difference, d=10

Last term, a n

=990

We know that, a

n

=a+(n−1)d

990=110+(n−1)10

⇒990–110=10n–10

⇒880+10=10n

⇒890=10n

⇒n=89

Therefore, the number of terms between 101 and 999 that are divisible by 2 and 5 are 89.