how many natural numbers are there from 1 to 1000 which have none of their digits repeated
Answers
Answered by
15
three digit numbers 9×9×8=648
2 digit numbers 9×9=81
total 729 numbers
there are 10 digits
0 1 2 3 4 5 6 7 8 9
2 digit numbers 9×9=81
total 729 numbers
there are 10 digits
0 1 2 3 4 5 6 7 8 9
Answered by
20
Answer:
Step-by-step explanation: 1 digit number =9
2 digit number = 9×9=81
3 digit number=9×9×8=648
Add.. 648+81+9=738...hope it helps you☺
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