Question

how many natural numbers lie between the following pairs of numbers (100 square and 101 square) , (90 square and 91 square ) , (1000 square 1001 square )

Answer 1

Answer:

200

180

2000

Step-by-step explanation:

a^2-b^2 = (a+b)(a-b)

101^2 -100^2-1

= (101+100*(101-100)-1

= 201*1 -1

= 200

91^2-90^2 -1

=(91+90)(91-90)-1

=181*1 -1

=180

1001^2-1000^2 -1

= (1001+1000)*(1001-1000) -1

= 2001*1 -1

= 2000