how many negative and positive charge in 250gm water
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Answered by
1
Mass of water= 250g
Molecular weight= 18g
No. Of moles of water= 250/18 = 13.888
No. Of moles in 250g = 13.888×6.022×10^23
=8.36×10^24
No. Of protons in one molecule of water = 10
Charge on one proton = 1.6×10^-19 C
Total +ve charge = 10×1.6×10^-19×8.36×10^24
=1.338×10^7 C
dilip07:
why not we can use n=m/Me formula where n=no of electron .m=mass of matter .Me=mass of electron
anyway thank you
Answered by
2
Mass of water= 250g
Molecular weight= 18g
No. Of moles of water= 250/18 = 13.888
No. Of moles in 250g = 13.888×6.022×10^23
=8.36×10^24
No. Of protons in one molecule of water = 10
Charge on one proton = 1.6×10^-19 C
Total +ve charge = 10×1.6×10^-19×8.36×10^24
=1.338×10^7 C (ans)
Therefore, total -ve charge= -10×1.6×10^-19×8.36×10^24(ans)
Molecular weight= 18g
No. Of moles of water= 250/18 = 13.888
No. Of moles in 250g = 13.888×6.022×10^23
=8.36×10^24
No. Of protons in one molecule of water = 10
Charge on one proton = 1.6×10^-19 C
Total +ve charge = 10×1.6×10^-19×8.36×10^24
=1.338×10^7 C (ans)
Therefore, total -ve charge= -10×1.6×10^-19×8.36×10^24(ans)
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