THE SUM OF CUBES OF THREE NUMBER WHICH IN THE RATIO OF 1: 2: 3: IN 972 . FIND THE NUMBER.
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Given ratio=1:2:3
Let the numbers be x,2x, 3x
Cube of the numbers=x^3,8x^3,27x^3
Sum of cubes of 3 numbers=972
According to question
x^3+8x^3+27x^3=972
36x^3=972
x^3=972/36
x^3=162/6=27
x^3=27
x=3
Hence, the numbers are 3,6,9
Let the numbers be x,2x, 3x
Cube of the numbers=x^3,8x^3,27x^3
Sum of cubes of 3 numbers=972
According to question
x^3+8x^3+27x^3=972
36x^3=972
x^3=972/36
x^3=162/6=27
x^3=27
x=3
Hence, the numbers are 3,6,9
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