How many neutrons are present in 180 ml water at 127° Celsius and 0.831 ATM pressure?the
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Answer:
Number of neutrons present in 6.022×1023 molecules of 8×6.022×1023=4.8176×1024.
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Since m=ρ×V,
m=18 g
Hence number of molecules of H2O=1×6.022×10 23
Number of moles=
18
18
=1
Number of neutrons present in a molecule of H2O=2+6=8
Number of neutrons present in 6.022×10 23
molecules of 8×6.022×10 23
=4.8176×10 24
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