How many no of atom present in 18.24 g of magnesium
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Answer:
4.577 x 10^23
Explanation:
Moles of Mg = 18.24/24 = 0.76
No of atoms of Mg = Moles x Avogadro number
= 0.76 x 6.023 x 10^23
= 4.577 x 10^23
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