Chemistry, asked by ritu8767089901, 9 months ago

How many no of atom present in 18.24 g of magnesium

Answers

Answered by AykkuMithun

0

Answer:

4.577 x 10^23

Explanation:

Moles of Mg = 18.24/24 = 0.76

No of atoms of Mg = Moles x Avogadro number

= 0.76 x 6.023 x 10^23

= 4.577 x 10^23

Previous Question

Next Question

Similar questions

Computer Science, 4 months ago

Write a program to display the average of three numbers 25,40 and 75.

Science, 4 months ago

1. Which of the following friction must overcome before an object can be set in motion? (a) Sliding friction (b) Static friction (c) Rolling friction (d) All of these...

Geography, 4 months ago

7. Length, breadth and height of a rectangular tank is 25 m, 20 m and 10 m respectively. Find the cost of painting its outer surface at * 3 per square metre.

India Languages, 9 months ago

ek Pramanik mulga story in marathi...

Math, 9 months ago

सरल करना है {20/(5-3)-1}-(3*6*3/9)+{(22*28/14/11)*4...

Physics, 1 year ago

Find the distance covered by a particle during the time interval t = 0 and t = 10s for which the speed time ajraph is shown in fingure...

Hindi, 1 year ago

Short defination of shant ras...

English, 1 year ago

Make a meaningful sentence by using the given phrase 'get through '...