Question

How many no. Of carbon atoms are present in 540g of glucose

Answer 1

Answer:

1 mole of glucose has a molecular weight of 180 g

Do taking mole first

$mole = \frac{540}{180} = 3moles$

$1mole = 6.023 \times {10}^{23} atoms$

Therefore there would be

$54 \times {10}^{23 \: }atoms$