Question

how many no of e are present in one cup (180g)of water

Answer 1

Answer:

6.022×10^25.

Explanation:

Molar mass of H2O= 18 gm.

Therefore, in one cup of water, number of water moles present = 180/18 = 10.

There are 6.022×10^23 molecules in one mole of water. Therefore, in 10 moles of water, number of molecules present is 60.22×10^23 . [since it is multiplied by 10]

Now,

Number of electrons in one molecule of water = (1×2 + 8) [since there is one electron in each atom of H and there are two H atoms in the molecule. Also, there are 8 electrons in each atom of O]

= 10.

Thus, number of electrons in one cup of water = ( 10× 60.22×10^23)

= 6.022×10^25.

Answer is 6.022×10^25.

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Answer 2

Answer:

180g of water =10mole of water

1mole=6.022 X 10*23 atoms

1atom of water has 18 electrons

hence,total electrons are

10 X 6.022 X 10*23 X 18 = 1.083 X 10*26