how many number of molecule are present in 64gm of CH4
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CH4 has a molar mass of 12+4=16g
no. of moles of CH4 in 64 g = 64/16=4
NO. OF MOLECULES= 4×6.022×10^23=24.088×10^23=2.4088×10^24
no. of moles of CH4 in 64 g = 64/16=4
NO. OF MOLECULES= 4×6.022×10^23=24.088×10^23=2.4088×10^24
Answered by
1
We know,
No. of molecules = No. Of Moles × Avogadro's number
No. Here,
Molecular Weight = 64 g
Molar mass of CH₄ = 12 + 4 = 16 g
No. Of moles = Molecular weight/Molar mass = 64/16 = 4g
Thus,
No. of molecules in CH₄ = 6.022 × 10²³ × 4 = 24.088 × 10²³ molecules
No. of molecules = No. Of Moles × Avogadro's number
No. Here,
Molecular Weight = 64 g
Molar mass of CH₄ = 12 + 4 = 16 g
No. Of moles = Molecular weight/Molar mass = 64/16 = 4g
Thus,
No. of molecules in CH₄ = 6.022 × 10²³ × 4 = 24.088 × 10²³ molecules
mrOogway:
Sorry I did a huge mistake but niw I have rectified it.
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