Question

How
many number of oxygen molecule are required to produce 0.22g of co2 according to reaction?
CO2 +O2 CO2​

Answer 1

Correct question:

How many number of oxygen molecules are required to produce 0.22g of CO2 according to reaction?

C+O2 ==> CO2

━━━━━━━━━━━━━━━━

SOLUTION:

Given:

• Weight of CO2= 0.22g

According to the reaction,

$C+ {O}_{2} \longrightarrow C{O}_{2}$

1 mole of CO2 is produced from 1 mole of Oxygen molecules

→ 44g of CO2 is produced from 32g of O2

→ 1g of CO2 is produced from 32÷44g of O2

→0.22g of Co2 is produced from $\dfrac{32}{44} \times 0.22$g of Oxygen

= 0.16g of Oxygen

━━━━━━━━━━━━━━━━

Now, we know that 1 mole of any substance constitutes $6.022 \times {10}^{23}$

smaller particles

Thus,

32g of O2 has $6.022 \times {10}^{23}$oxygen molecules

→ 1 g of O2 has $\dfrac{6.022 \times {10}^{23} }{32}$oxygen molecules

→0.16 g has:

$= \dfrac{6.022 \times {10}^{23} }{32} \times 0.16$oxygen molecules

$= 0.0311 \times {10}^{23}$oxygen molecules

$\red{\large{\bold{\boxed{= 3.11 \times {10}^{21}}}}}$oxygen molecules

Answer 2

Correct question:

How many number of oxygen molecules are required to produce 0.22g of CO2 according to reaction?

C+O2 ==> CO2

━━━━━━━━━━━━━━━━

SOLUTION:

Given:

Weight of CO2= 0.22g

According to the reaction,

C+ {O}_{2} \longrightarrow C{O}_{2}C+O

2

⟶CO

2

1 mole of CO2 is produced from 1 mole of Oxygen molecules

→ 44g of CO2 is produced from 32g of O2

→ 1g of CO2 is produced from 32÷44g of O2

→0.22g of Co2 is produced from \dfrac{32}{44} \times 0.22

44

32

×0.22 g of Oxygen

= 0.16g of Oxygen

━━━━━━━━━━━━━━━━

Now, we know that 1 mole of any substance constitutes 6.022 \times {10}^{23}6.022×10

23

smaller particles

Thus,

32g of O2 has 6.022 \times {10}^{23}6.022×10

23

oxygen molecules

→ 1 g of O2 has \dfrac{6.022 \times {10}^{23} }{32}

32

6.022×10

23

oxygen molecules

→0.16 g has:

= \dfrac{6.022 \times {10}^{23} }{32} \times 0.16=

32

6.022×10

23

×0.16 oxygen molecules

= 0.0311 \times {10}^{23}=0.0311×10

23

oxygen molecules

\red{\large{\bold{\boxed{= 3.11 \times {10}^{21}}}}}

=3.11×10

21

oxygen molecules