how many numbers are there between 100and 1000 which are divisible by 5
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Answered by
0
105,110,115......995
it is an AP so
995 = 105+(n-1)*5
890=5n-5
895=5n
n=199
it is an AP so
995 = 105+(n-1)*5
890=5n-5
895=5n
n=199
Answered by
3
100,105,110............1000
a=100
an=1000
d=5
n=?
an=a+(n-1)×d
1000=100+(n-1)×5
1000=100+5n-5
1000=95+5n
1000-95=5n
905÷5=n
n=181
a=100
an=1000
d=5
n=?
an=a+(n-1)×d
1000=100+(n-1)×5
1000=100+5n-5
1000=95+5n
1000-95=5n
905÷5=n
n=181
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